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5n^2-3=n
We move all terms to the left:
5n^2-3-(n)=0
We add all the numbers together, and all the variables
5n^2-1n-3=0
a = 5; b = -1; c = -3;
Δ = b2-4ac
Δ = -12-4·5·(-3)
Δ = 61
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{61}}{2*5}=\frac{1-\sqrt{61}}{10} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{61}}{2*5}=\frac{1+\sqrt{61}}{10} $
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